The ‘dissapearing sock’ phenomena is somewhat of a cliche. It never ceases to irritate me, though, when it happens to me. I was putting my clothes away when I found an extra sock. I looked in the sock drawer and there was a match for it. Hooray! I then picked up the last shirt, and there was an unpaired sock lying underneath it. Gah!
The thing that makes sock loss noticable is the fact that you don’t have one to pair it up with when it comes time to put it back in the drawer. If you always lost socks in pairs, then eventually you’d have to get more, but this seems like a natural enough thing to me. If you run out of socks, it’s because maybe you threw some away because they got holes in them – or perhaps they undergo a spontaenous decay process. In any event, the only thing that causes me irritation is when I’ve got a sock with nothing to pair it up with.
Now for the mathematical analysis. Consider two possible cases. In case one, you’ve got an odd number of socks when you put your load in the washing machine. If we lose no socks, we’ll be mad when laundry is finished because then we’ll still have an odd number of socks and therefore one will be left without a pair. If we lose one, howerver, we’ll feel OK because all the socks will have matches. In case two, you’ve got an even number of socks. Here, if you lose one or three, you’ll be mad, but losing two or zero will leave you feeling OK. If we assume that N is large enough, then regardless of whether N is even or odd, the probability of losing one sock is the same, as it is for two or three socks. Let P1 = the probability that one sock will be lost, P2 = the probabilty that two socks will be lost, etc:
Let’s compute the possibilty of unhappiness after a given load of laundry:
If we started with an even number of socks, then the chance that we will be unhappy after doing the laundry is:
P1 + P3 + P5 …
Likewise, if we started with an odd number of socks, then the chance that we will be unhappy is:
P0 + P2 + p4 …
If we assume that there’s a 50% chance we’ll start with an even number of socks and a 50% chance that we start with an odd number of socks, then the total chance we’ll be unhappy is:
(0.5)(P1 + P3 + P5 …) + (0.5)(P0 + P2 + P4 …) = (0.5)(P0 + P1 + P2 + P3 + P4 + P5 ….)
Because P0…PN represents all possible sock losses, the the sum of P0…PN must be one.
Meaning that after every round of laundry, there’s a 50% chance of us being unhappy about a missing sock.
Maybe I’ll just buy new socks instead of washing them.